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12 April 2023
100w max
6 of 6 found this helpful A solar panel with dimensions of 1080 x 710 x 2.5 mm (1.08 x 0.71 meters) would be much too small to produce 300 watts of power. To illustrate this, we can analyze the relationship between solar panel size and power output, which is largely determined by the efficiency of the solar cells used in the panel.
Solar panel efficiency is generally expressed as a percentage and represents the amount of sunlight that is converted into electricity by the panel. Currently, the efficiency of commercially available solar panels ranges from about 15% to 23%. Let's assume a relatively high efficiency of 20% for our calculations.
First, let's determine the surface area of the given solar panel:
Area = Length x Width = 1.08 m x 0.71 m = 0.7668 m²
Next, let's calculate the solar energy incident on the panel. The solar constant, which represents the amount of solar energy received at the top of Earth's atmosphere, is approximately 1,360 watts per square meter (W/m²). However, this value decreases as sunlight passes through the atmosphere. On a clear day, the solar irradiance at the Earth's surface is roughly 1,000 W/m². This value can be used as a rough estimate of the sunlight received by a solar panel.
Now, let's multiply the solar irradiance by the panel's area and efficiency to estimate its power output:
Power output = Solar irradiance x Area x Efficiency
Power output = 1,000 W/m² x 0.7668 m² x 0.20 = 153.36 watts
As calculated, a solar panel of 1080 x 710 x 2.5 mm dimensions with 20% efficiency would produce approximately 153.36 watts, which is much less than the desired 300 watts.
In conclusion, a solar panel with dimensions of 1080 x 710 x 2.5 mm is far too small to produce 300 watts of power, even when assuming a high efficiency of 20%. The calculated power output of approximately 153.36 watts is less than half of the required output. To achieve 300 watts, a larger solar panel would be needed, or multiple smaller panels could be combined to reach the desired power output.